본잡 이어가기/BaekJoon

[백준 / Java] 10817번

UMING 2022. 6. 16. 04:14

https://www.acmicpc.net/problem/10817

 

10817번: 세 수

첫째 줄에 세 정수 A, B, C가 공백으로 구분되어 주어진다. (1 ≤ A, B, C ≤ 100)

www.acmicpc.net

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
	Scanner scanner= new Scanner(System.in);
	
	int number1 = scanner.nextInt();
	int number2 = scanner.nextInt();
	int number3 = scanner.nextInt();

	
	if(((number1>number2)&&(number2>number3))||((number2>number1)&&(number2<number3))) {
		System.out.println(number2);}
	
	else if (((number2>number1)&&(number1>number3))||((number1<number3)&&(number1>number2))) {
			System.out.println(number1);}	
	
	else if(((number1>number3)&&(number3>number2))||((number3<number2)&&(number3>number1))) {
			System.out.println(number3);
	}
	else if(((number1==number2)&&(number2>number3))||((number2==number3)&&(number3>number1))){
		System.out.println(number2);
	}
	else if(((number1==number3)&&(number3>number2))||((number1==number2)&&(number2==number3))){
		System.out.println(number3);
	}
	else if(((number1==number2)&&(number1<number3))||((number1==number3)&&(number3<number2))){
		System.out.println(number1);
	}
	else if((number2==number3)&&(number2<number1)){
		System.out.println(number3);
	}
	}
		
	}

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